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-70=+13t-4.9t^2
We move all terms to the left:
-70-(+13t-4.9t^2)=0
We get rid of parentheses
4.9t^2-13t-70=0
a = 4.9; b = -13; c = -70;
Δ = b2-4ac
Δ = -132-4·4.9·(-70)
Δ = 1541
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{1541}}{2*4.9}=\frac{13-\sqrt{1541}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{1541}}{2*4.9}=\frac{13+\sqrt{1541}}{9.8} $
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